# Business Statistics Assignment 2

**Topics:**Harshad number, Accounts receivable, Probability theory

**Pages:**6 (495 words)

**Published:**April 22, 2015

Group Assignment

Business Statistics

CBEB1109

Tutorial : Tuesday 11.00am – 12.00pm

Instructor : Dr. Sharifah Latifah Binti Syed A Kadir

Group : Group 2

Group Members:

1.

Kao Wei Jian

CEA 130028

2.

Lim Kin Chun

CEA 130041

3.

Amirul Asyraaf bin Azhar

CEA 130002

4.

Nur Hasfaiza bt Mohd Zaid

CEA 130063

5.

Muhammad Hamdin Zarif Bin Mohd Zaidi

CEA 100062

6.

Lim Sin Pei

CEA 130043

7.

Wong Siew Yen

CEA 130097

1. Of 100 individuals who applied for systems analyst positions with a large firm during the past year, 40 had some prior work experience, 30 had a professional certificate and 20 of them had both work experience and a certificate. a Determine if work experience and certification are independent events. Let A = Prior Work experience

B = Professional Certificate

A

A’

Total

B

20

30

50

B’

40

10

50

Total

60

40

100

=

= 0.4

P(A) =

= 0.6

, so it is not an independent event.

b What is the probability that a randomly chosen applicant,

i had either work experience or a certificate?

) =

=

= 0.9

ii has neither work experience nor a certificate?

iii has a certificate if he has some previous work experience?

= 0.33

2.Because of economic conditions, a firm reports that 30 percent if its accounts receivable from other business firms are overdue. If an accountant takes a random sample of 10 such accounts, determine the probability that p=30% @ 0.3

n=10

X~B(10,0.3)

a.none of the account is overdue

By referring to the Binomial Table,

P(X=0) = 1 – P(X ≥ 1)

= 1 – 0.9718

= 0.0282

b.exactly 2 accounts are overdue

By referring to the Binomial Table,

P(X=2) = P(X ≥ 2) – P(X ≥ 3)

= 0.8507 – 0.6172

= 0.2335

c. less than 5 accounts are overdue.

By referring to the Binomial Table,

P(X3.The amount of time required per individual at a bank teller machine has been found to be approximately normal distribution with mean 130sec and std. dev. 45 sec.

What is the probability that a randomly selected individual a.will require less than 100 sec to complete a transaction?

µ = 130 secsd = 45 secx = 100 sec

Z = X - µ sd = 100 – 130

45

= - 0.67

-0.67

0

P=

0.2514

b.spend between 2.00 and 3.00 mins at the bank tell machine?

µ = 130 sec sd. Dev= 45 secx = 120 sec and 180 sec

Z = X - µ

sd

= 120 – 130 ≤ Z ≤ 180 - 130

45 45

= - 0.22 ≤ Z ≤ 1.11

-0.22

0

1.11

1.11 ≥ Z ≥- 0.22

1-(Z>1.11)-(Z

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